Python实现图片九宫格切图的方法

核心代码解析

# -*- coding: utf-8 -*-
'''
将一张图片填充为正方形后切为9张图
'''
from PIL import Image
import sys
#将图片填充为正方形
def fill_image(image):
  width, height = image.size
  #选取长和宽中较大值作为新图片的
  new_image_length = width if width > height else height
  #生成新图片[白底]
  new_image = Image.new(image.mode, (new_image_length, new_image_length), color='white')
  #将之前的图粘贴在新图上，居中
  if width > height:#原图宽大于高，则填充图片的竖直维度
    #(x,y)二元组表示粘贴上图相对下图的起始位置
    new_image.paste(image, (0, int((new_image_length - height) / 2)))
  else:
    new_image.paste(image, (int((new_image_length - width) / 2),0))
  return new_image
#切图
def cut_image(image):
  width, height = image.size
  item_width = int(width / 3)
  box_list = []
  # (left, upper, right, lower)
  for i in range(0,3):#两重循环，生成9张图片基于原图的位置
    for j in range(0,3):
      #print((i*item_width,j*item_width,(i+1)*item_width,(j+1)*item_width))
      box = (j*item_width,i*item_width,(j+1)*item_width,(i+1)*item_width)
      box_list.append(box)

  image_list = [image.crop(box) for box in box_list]
  return image_list
#保存
def save_images(image_list):
  index = 1
  for image in image_list:
    image.save('./python'+str(index) + '.png', 'PNG')
    index += 1

if __name__ == '__main__':
  file_path = "python.jpeg"
  image = Image.open(file_path)
  #image.show()
  image = fill_image(image)
  image_list = cut_image(image)
  save_images(image_list)