Python检查与修改目录文件权限的完整方案
本文介绍如何使用Python脚本检查特定用户对文件或目录的访问权限,并提供批量修改目录权限的方法。通过结合os、stat和pwd模块,实现了对Nginx日志目录等关键路径的读写执行权限校验与修正,适用于服务器运维场景。
Python权限检查与修改脚本实现
为了节省篇幅,这里直接展示核心代码实现。
# -*- coding: utf-8 -*-
# @author flynetcn
import sys, os, pwd, stat, datetime;
LOG_FILE = '/var/log/checkDirPermission.log';
nginxWritableDirs = [
'/var/log/nginx',
'/usr/local/www/var',
];
otherReadableDirs = [
'/var/log/nginx',
'/usr/local/www/var/log',
];
dirs = [];
files = [];
def logger(level, str):
logFd = open(LOG_FILE, 'a');
logFd.write(datetime.datetime.now().strftime('%Y-%m-%d %H:%M:%S.%f')+": "+("WARNING " if level else "NOTICE ")+str);
logFd.close();
def walktree(top, callback):
for f in os.listdir(top):
pathname = os.path.join(top, f);
mode = os.stat(pathname).st_mode;
if stat.S_ISDIR(mode):
callback(pathname, True);
walktree(pathname, callback);
elif stat.S_ISREG(mode):
callback(pathname, False);
else:
logger(1, "walktree skipping %s\n" % (pathname));
def collectPath(path, isDir=False):
if isDir:
dirs.append(path);
else:
files.append(path);
def checkNginxWritableDirs(paths):
uid = pwd.getpwnam('nginx').pw_uid;
gid = pwd.getpwnam('nginx').pw_gid;
for d in paths:
dstat = os.stat(d);
if dstat.st_uid != uid:
try:
os.chown(d, uid, gid);
except:
logger(1, "chown(%s, nginx, nginx) failed\n" % (d));
def checkOtherReadableDirs(paths, isDir=False):
for d in paths:
dstat = os.stat(d);
if isDir:
checkMode = 5;
willBeMode = dstat.st_mode | stat.S_IROTH | stat.S_IXOTH;
else:
checkMode = 4;
willBeMode = dstat.st_mode | stat.S_IROTH;
if int(oct(dstat.st_mode)[-1:]) & checkMode != checkMode:
try:
os.chmod(d, willBeMode);
except:
logger(1, "chmod(%s, %d) failed\n" % (d, oct(willBeMode)));
if __name__ == "__main__":
for d in nginxWritableDirs:
walktree(d, collectPath)
dirs = dirs + files;
checkNginxWritableDirs(dirs);
dirs = [];
files = [];
for d in otherReadableDirs:
walktree(d, collectPath)
checkOtherReadableDirs(dirs, True);
checkOtherReadableDirs(files, False);
补充知识:Python中获取某个用户对某个文件或目录的访问权限
在Python中,我们通常可以使用os.access()函数来获取当前用户对某个文件或目录是否有某种权限。然而,若要获取特定用户(非当前执行用户)对某个文件或目录的权限,Python标准库中没有直接提供简便方法。因此,这里编写了一个辅助函数,利用stat和pwd模块来实现这一功能。
获取特定用户访问权限的方法
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import os
import pwd
import stat
def is_readable(path, user):
user_info = pwd.getpwnam(user)
uid = user_info.pw_uid
gid = user_info.pw_gid
s = os.stat(path)
mode = s[stat.ST_MODE]
return (
((s[stat.ST_UID] == uid) and (mode & stat.S_IRUSR > 0)) or
((s[stat.ST_GID] == gid) and (mode & stat.S_IRGRP > 0)) or
(mode & stat.S_IROTH > 0)
)
def is_writable(path, user):
user_info = pwd.getpwnam(user)
uid = user_info.pw_uid
gid = user_info.pw_gid
s = os.stat(path)
mode = s[stat.ST_MODE]
return (
((s[stat.ST_UID] == uid) and (mode & stat.S_IWUSR > 0)) or
((s[stat.ST_GID] == gid) and (mode & stat.S_IWGRP > 0)) or
(mode & stat.S_IWOTH > 0)
)
def is_executable(path, user):
user_info = pwd.getpwnam(user)
uid = user_info.pw_uid
gid = user_info.pw_gid
s = os.stat(path)
mode = s[stat.ST_MODE]
return (
((s[stat.ST_UID] == uid) and (mode & stat.S_IXUSR > 0)) or
((s[stat.ST_GID] == gid) and (mode & stat.S_IXGRP > 0)) or
(mode & stat.S_IXOTH > 0)
)
使用方法
权限检查函数的调用示例
print is_readable('/home', root)
print is_writable('/home', root)
print is_executable('/home', root)
print is_readable('/tmp', admin)
print is_writable('/tmp', admin)
print is_executable('/tmp', admin)
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