Python实现带余额校验的循环购物车程序

# -*- coding: utf-8 -*-
__author__ = 'hujianli'

shopping = [
 ("iphone6s", 5000),
 ("book python", 81),
 ("iwach", 3200),
 ("电视机", 2200)
]

def zero(name):
 if len(name) == 0:
  print("\033[31;1m您的输入不能为空，清重新输入~~\033[0m")
  exit()
 else:
  return True

def crre(name):
 if int(name) not in range(len(shopping)):
  print("\033[31;1m您输入了错误的序列号，请重新输入~~\033[0m")
  exit()
 else:
  return True



gongzi = input("请输入您目前的工资：")
if not gongzi.isdigit():
 crre()
elif len(gongzi) == 0:
 zero()
else:
 gongzi = int(gongzi)
 print("=========================================")
 print("===要购买的列表清单如下： ")
 for i,j in enumerate(shopping):
  print(i, j[0], j[1])

shopping_cart = []
while True:
 choice = input("请输入你要购买的商品,输入q或者exit退出选择回到购物车列表： ")
 if choice.isdigit():
  zero(choice)
  crre(choice)
  choice = int(choice)
  goods = shopping[choice]
  if gongzi < int(goods[1]):
   gongzi -= goods[1]
   print("===您的工资余额不够使用了，还差\033[1;31m{}\033[0m请努力挣钱===.".format(abs(gongzi)))
  else:
   print("您选购的商品:\033[1;32m %s \033[0m 已经加入到购物车.." % (goods[0]))
   shopping_cart.append(goods)
   gongzi -= goods[1]
   print("您的工资余额还剩下:\033[30;42m %s\033[0m"% (gongzi))
 elif (choice == "q") or (choice == "exit"):
  break

print('\033[30;42m你已购商品列表\033[0m'.center(42,'-'))
for i,j in enumerate(shopping_cart):
 print("\033[1;32m" + str(i+1) + " " + str(j[0]) + " " + str(j[1]) + "\033[0m")