Python利用pynput实现微信表情包自动发送脚本

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发布时间：2026-10-14| 4人浏览过

原创

本文介绍如何使用Python的pynput库实现微信表情包自动发送功能。通过控制键盘输入表情代码并模拟鼠标点击发送按钮，配合随机选择表情列表，可批量发送指定数量的表情包。代码包含表情库定义、次数输入验证及循环控制逻辑，适用于测试或趣味互动场景。

Python微信表情包自动发送脚本实现

使用Python脚本实现微信表情包自动发送功能，具体实现代码如下：

核心代码解析


# -*- coding = utf-8 -*-
# @Time : 2021/1/26 15:19
# @Author : 陈良兴
# @File : 微信表情包炸群.py
# @Software : PyCharm

# 运行程序 > 输入次数 > 回车 > 打开微信对话框 > 将鼠标放置在“发送”按钮处即可

from pynput.keyboard import Controller as KB        #控制键盘输入
from pynput.mouse import Controller,Button         #控制鼠标点击
import time
import random

Wechat_expression = [
  "[微笑]","[撇嘴]","[色]","[发呆]","[得意]","[流泪]","[害羞]","[闭嘴]","[睡]","[大哭]","[尴尬]",
  "[发怒]","[调皮]","[呲牙]","[惊讶]","[难过]","[囧]","[抓狂]","[吐]","[偷笑]","[愉快]","[白眼]",
  "[傲慢]","[困]","[惊恐]","[憨笑]","[悠闲]","[咒骂]","[疑问]","[嘘]","[晕]","[衰]","[骷髅]","[猪头]",
  "[敲打]","[再见]","[擦汗]","[抠鼻]","[鼓掌]","[坏笑]","[右哼哼]","[鄙视]","[委屈]","[快哭了]",
  "[阴险]","[亲亲]","[可怜]","[笑脸]","[生病]","[脸红]","[破涕为笑]","[恐惧]","[失望]","[无语]",
  "[嘿哈]","[捂脸]","[奸笑]","[机智]","[皱眉]","[耶]","[吃瓜]","[加油]","[汗]","[天啊]","[Emm]",
  "[社会社会]","[旺柴]","[好的]","[打脸]","[哇]","[翻白眼]","[666]","[让我看看]","[叹气]","[苦涩]",
  "[裂开]","[嘴唇]","[爱心]","[心碎]","[拥抱]","[强]","[弱]","[握手]","[胜利]","[抱拳]","[勾引]",
  "[拳头]","[OK]","[合十]","[啤酒]","[咖啡]","[蛋糕]","[玫瑰]","[凋谢]","[菜刀]","[便便]","[月亮]",
  "[太阳]","[礼物]","[红包]","[發]","[福]","[跳跳]","[发抖]","[转圈]","[炸弹]","[庆祝]","[烟花]"
]

#键盘控制函数
def keyboardInput(string):
  keyboard = KB()
  keyboard.type(string)

#鼠标控制函数
def mouseClick():
  mouse = Controller()
  mouse.press(Button.left)
  mouse.release(Button.left)

#响应函数
def response(number):
  time.sleep(5)             #延迟5s响应
  for i in range(number):
    sentence = random.choice(Wechat_expression)
    keyboardInput(sentence)
    mouseClick()
    time.sleep(0.4)           #每条消息间隔0.4秒


if __name__ == "__main__":
  while True:
  	print("\033[1;32m发动机已启动，随时可以出发！\033[0m")
    Num = input("\033[1;32m请输入轰炸次数：\033[0m")
    if Num.isdigit():
      response(int(Num))
      print("\033[1;33m报告长官，轰炸完毕，请求下一步作战计划！！！\033[0m")
    else:
      print("\033[1;31m输入错误，请重新输入一个整数！！！\033[0m")

    #询问是否继续
    answer = input("\033[1;34m是否执行下一次作战计划？(y 或者 n)：\033[0m")
    if answer == "y":
      print("\033[1;33m继续轰炸！！！\033[0m")
      continue
    if answer == "n":
      print("\033[1;33m停止轰炸，给他们喘口气！！！\033[0m")
      break
    else:
      print("\033[1;31m输入错误，请输入“y”或者“n”!!!\033[0m")