Python中将字典转换为对象以支持点号访问属性

database = [
  {
    "name": "18D_Block",
    "xcc":{  
      "component": {
        "core":[],
        "platform":[]
      },
    },
    "uefi":{  
      "component": {
        "core":[],
        "platform":[]
      },
    }
  }
]
class Dict(dict):
  __setattr__ = dict.__setitem__
  __getattr__ = dict.__getitem__
 
def dict_to_object(dictObj):
  if not isinstance(dictObj, dict):
    return dictObj
  inst=Dict()
  for k,v in dictObj.items():
    inst[k] = dict_to_object(v)
  return inst
# 转换字典成为对象，可以用"."方式访问对象属性
res = dict_to_object(database[0])
print res.name
print res.xcc
print res.xcc.component
print res.xcc.component.core

vars()函数详解

>>>print(vars())
{'__builtins__': <module '__builtin__' (built-in)>, '__name__': '__main__', '__doc__': None, '__package__': None}

>>> class Test:
...   a = 1
... 

>>> print(vars(Test))
{'a': 1, '__module__': '__main__', '__doc__': None}

>>> test = Test()
>>> print(vars(test))
{}

>>> x = 1
>>> scope = vars()
>>> scope["x"]
1