Python批量处理文件与文件夹的脚本实现

核心处理逻辑与代码实现

# -*- coding: utf-8 -*-
import os,shutil
import sys
import numpy as np
##########批量删除不同文件夹下的同名文件夹#############
def arrange_file(dir_path0):
 for dirpath,dirnames,filenames in os.walk(dir_path0):
  if 'my_result' in dirpath:
   # print(dirpath)
   shutil.rmtree(dirpath)


##########批量在不同文件夹下新建同名子文件夹并把文件搬移到子文件夹#############
def arrange_file(dir_path0):
 for dirpath,dirnames,filenames in os.walk(dir_path0):
  for files in filenames:
   total_path = os.path.join(dirpath,files)
   root_path,file_path = total_path.split(dir_path,1)
   if 'png' in file_path:
    new_file_path = '.' + file_path[:-9] + 'new_file_name/'
    # print(file_path)
    # print(new_file_path)
    # print(new_file_path + file_path[-9:])
    # if not os.path.exists(new_file_path):
    #  os.makedirs(new_file_path)
    # shutil.move('.' + file_path,new_file_path + file_path[-9:])

##########批量删除不同文件夹下符合条件的文件##################
def arrange_file(dir_path0):
 for dirpath,dirnames,filenames in os.walk(dir_path0):
  for files in filenames:
   total_path = os.path.join(dirpath,files)
   # print(total_path)
   if 'jpg' in total_path and 'labels' in total_path:
    img = cv2.imread(total_path)
    if np.sum(img) == 0:
     print(total_path)
     os.remove(total_path)

###########批量把文件搬移到上一层文件夹并删除当前文件夹########
def arrange_file(dir_path0):
 for dirpath,dirnames,filenames in os.walk(dir_path0):
  for files in filenames:
   total_path = os.path.join(dirpath,files)
   root_path,file_path = total_path.split(dir_path0,1)
   # print(file_path[:-48])
   # return 0
   if 'jpg' in file_path:
    new_file_path = dir_path0 + file_path[:-48]
    shutil.move(dir_path0 + file_path,new_file_path + file_path[-9:])

 for dirpath,dirnames,filenames in os.walk(dir_path0):
  file_path = dirpath.split('./your_total_path')[1]
  if 'keywords' in file_path:
   # print(dirpath) 
   shutil.rmtree(dirpath)

if __name__=='__main__':
 dir_path0 = './your_total_path'
 arrange_file(dir_path0)