Python Tkinter 实现简单登录界面

雨后青山

发布时间：2026-10-13| 6人浏览过

原创

本文介绍如何使用 Python 的 Tkinter 库构建一个基础的登录界面。通过定义 Reg 类，利用 Label、Entry 和 Button 组件布局账户与密码输入框，并编写 Submit 方法处理验证逻辑。当输入的用户名为 admin 且密码为 123 时提示成功，否则报错，同时清空输入框。

Python Tkinter 登录界面实现

具体实现代码如下所示：


from tkinter import *
 
class Reg (Frame):
  def __init__(self,master):
    frame = Frame(master)
    frame.pack()
    self.lab1 = Label(frame,text = "账户:")
    self.lab1.grid(row = 0,column = 0,sticky = W)
    self.ent1 = Entry(frame)
    self.ent1.grid(row = 0,column = 1,sticky = W)
    self.lab2 = Label(frame,text = "密码:")
    self.lab2.grid(row = 1,column = 0)
    self.ent2 = Entry(frame,show = "*")
    self.ent2.grid(row = 1,column = 1,sticky = W)
    self.button = Button(frame,text = "登录",command = self.Submit)
    self.button.grid(row = 2,column = 1,sticky = E)
    self.lab3 = Label(frame,text = "")
    self.lab3.grid(row = 3,column = 0,sticky = W)
    self.button2 = Button(frame,text = "退出",command = frame.quit)
    self.button2.grid(row = 3,column = 3,sticky = E)
  def Submit(self):
    s1 = self.ent1.get()
    s2 = self.ent2.get()
    if s1 == 'admin' and s2 == '123':
      self.lab3["text"] = "登陆成功"
    else:
      self.lab3["text"] = "用户名或密码错误!"
    self.ent1.delete(0,len(s1))
    self.ent2.delete(0,len(s2))
root = Tk()
root.title("用户登录")
app = Reg(root)
root.mainloop()