Python自动化实现每日FR文件压缩与Outlook邮件发送

import win32com.client as win32
import datetime
import os
import zipfile

#压缩文件夹函数
def zip_ya(startdir,file_news):
 file_news = startdir +'.rar' # 压缩后文件夹的名字
 z = zipfile.ZipFile(file_news,'w',zipfile.ZIP_DEFLATED) #参数一：文件夹名
 for dirpath, dirnames, filenames in os.walk(startdir):
 fpath = dirpath.replace(startdir,'') #这一句很重要，不replace的话，就从根目录开始复制
 fpath = fpath and fpath + os.sep or ''#这句话理解我也点郁闷，实现当前文件夹以及包含的所有文件的压缩
 for filename in filenames:
  z.write(os.path.join(dirpath, filename),fpath+filename)
  print ('压缩成功')
 z.close()

#创建文件夹函数
def mkdir(path):
 folder = os.path.exists(path)
 if not folder:   
 os.makedirs(path)  
 print "创建文件夹成功"
 else:
 print "文件夹已存在"

#发送邮件函数
def sendmail(path):
 sub = '上传FR文件申请'
 body = '@xx，\r请帮忙上传FR文件，谢谢！'
 outlook = win32.Dispatch('outlook.application')
 receiver = ['xxx@xx.com']
 ccreceiver = ['xxx@xx.com;xxx@xx.com;xxx@xx.com;xxx@xx.com']
 mail = outlook.CreateItem(0)
 mail.To = receiver[0]
 mail.Cc = ccreceiver[0]
 mail.Subject = sub.decode('utf-8')
 mail.Body = body.decode('utf-8')
 mail.Attachments.Add(path)
 mail.Send() 

#获取今天明天昨天的日期
today = datetime.date.today().strftime("%Y%m%d")
tomorrow = (datetime.date.today()+ datetime.timedelta(days=1)).strftime("%Y%m%d")
yesterday = (datetime.date.today()+ datetime.timedelta(days=-1)).strftime("%Y%m%d")

#定义文件路径
path='//tcent.cn/dfs/26.xx事业部/10.xx市场营销中心/04.xxx部/02.xxx组/FR文件上传/'
todaypath=path + today
todayfile = path + today + '.rar'
tomorrowpath=path + tomorrow
utodaypath=unicode(todaypath,'utf-8')
utodayfile=unicode(todayfile,'utf-8')
utomorrowpath=unicode(tomorrowpath,'utf-8')

#定义昨天的压缩文件
yesterdayfile=path + yesterday + '.rar'
uyesterdayfile=unicode(yesterdayfile,'utf-8')

#计算今天文件夹下的文件个数
filenum = 0 
for filename in os.listdir(utodaypath):
 filenum += 1

#创建明天的文件夹
mkdir(utomorrowpath) 

#删除昨天的压缩文件
if os.path.exists(uyesterdayfile): # 如果文件存在
 os.remove(uyesterdayfile) 
else:
 print('no such file:%s'%uyesterdayfile)

#获取今天是周几
weekoftoday=datetime.date.today().weekday()
#节假日列表
holiday=['20180924','20181001','20181002','20181003','20181004','20181005']
#补班列表
workday=['20180924','20180925']

#是否是周末
isweekend=(weekoftoday == 5 or weekoftoday == 6)
#是否是小长假
isholiday=today in holiday
#是否不要补班
isworkday=today not in workday
#文件夹是否为空
isnullfile=(filenum==0)

#判断是否要压缩文件并发送邮件
#周末、工作日放假的节假日、文件夹为空时不执行
#补班的周末例外
if isnullfile:
 pass
else:
 if ((isweekend or isholiday) and isworkday ):
 pass
 else:
  #压缩今天的文件夹
  zip_ya(utodaypath,today)
  #发送邮件
  sendmail(utodayfile)

@echo off 
cd D:\myprograms\sendmail
start python sendmail.py